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Example
Chosen measurement -50 ... +150 °C → 200 K span
range: 1 % from 200 K span = 2 K
Set minimum temperature -50 °C + 2 K = -48 °C
on the PT 100 simulator and calibrate the signal conditioner out-
put signal to 0.200 mA using the null potentiometer.
Mean temperatur e = (ϑ
max
+ ϑ
min
)/2
= (150 °C + (-50 °C))/2
= 50 °C
Set the 50 °C value on a PT 100 simulator
Then determine ∆I: ∆I = measured value from measuring
instrument - 10.000 mA
→ ∆I = 9.940 mA - 10.000 mA
= -0.060 mA
Then calibrate the output signal to (10.000 mA - ∆I) using the
span potentiometer i.e. her e an example.
"10.000 mA - (-0.060 mA) = 10.060 mA"
Then set the maximum temperature on the PT 100 simulator
(150 °C) and calibrate the output signal to 20.000 mA using the
lin potentiometer.
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